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Just as it says...
By What's Burning?
#344988
Was at work today and thinking about this and came up with another way to think about it.

In a stationary car or one moving at a constant speed, up and down are relative to up and down with respect to the ground.
When the car accelerates or decelerates the g forces on everything within the car change what up and down are, the g force vectors and the gravity vector can be added. If you're standing on a train as it pulls away from the station you lean forward to a position where you're balanced and effectively your body is on the up/down line created by adding the g force vector (pushing you back relative to the train) to the gravity vector. The same with the helium balloon, it always wants to go up but the acceleration of the car changes what up is.

If there is constant acceleration then the balloon with pull forward and up, if you hold a ball bearing to the top of the string where it's tied to the balloon and let it go it will fall following the line of the string to the bottom.


Acceleration and deceleration completely screw around with the theory or relative motion.
User avatar
By stonemonkey
#344998
Was at work today and thinking about this and came up with another way to think about it.

In a stationary car or one moving at a constant speed, up and down are relative to up and down with respect to the ground.
When the car accelerates or decelerates the g forces on everything within the car change what up and down are, the g force vectors and the gravity vector can be added. If you're standing on a train as it pulls away from the station you lean forward to a position where you're balanced and effectively your body is on the up/down line created by adding the g force vector (pushing you back relative to the train) to the gravity vector. The same with the helium balloon, it always wants to go up but the acceleration of the car changes what up is.

If there is constant acceleration then the balloon with pull forward and up, if you hold a ball bearing to the top of the string where it's tied to the balloon and let it go it will fall following the line of the string to the bottom.


Acceleration and deceleration completely screw around with the theory or relative motion.


In what way?
By What's Burning?
#345006
Was at work today and thinking about this and came up with another way to think about it.

In a stationary car or one moving at a constant speed, up and down are relative to up and down with respect to the ground.
When the car accelerates or decelerates the g forces on everything within the car change what up and down are, the g force vectors and the gravity vector can be added. If you're standing on a train as it pulls away from the station you lean forward to a position where you're balanced and effectively your body is on the up/down line created by adding the g force vector (pushing you back relative to the train) to the gravity vector. The same with the helium balloon, it always wants to go up but the acceleration of the car changes what up is.

If there is constant acceleration then the balloon with pull forward and up, if you hold a ball bearing to the top of the string where it's tied to the balloon and let it go it will fall following the line of the string to the bottom.


Acceleration and deceleration completely screw around with the theory or relative motion.


In what way?

In that it's easier to formulate speed or motion when it's at a constant. When you're accelerating and decelerating, a whole more complex world of mathematics needs to be in place.
User avatar
By stonemonkey
#345009
Was at work today and thinking about this and came up with another way to think about it.

In a stationary car or one moving at a constant speed, up and down are relative to up and down with respect to the ground.
When the car accelerates or decelerates the g forces on everything within the car change what up and down are, the g force vectors and the gravity vector can be added. If you're standing on a train as it pulls away from the station you lean forward to a position where you're balanced and effectively your body is on the up/down line created by adding the g force vector (pushing you back relative to the train) to the gravity vector. The same with the helium balloon, it always wants to go up but the acceleration of the car changes what up is.

If there is constant acceleration then the balloon with pull forward and up, if you hold a ball bearing to the top of the string where it's tied to the balloon and let it go it will fall following the line of the string to the bottom.


Acceleration and deceleration completely screw around with the theory or relative motion.


In what way?

In that it's easier to formulate speed or motion when it's at a constant. When you're accelerating and decelerating, a whole more complex world of mathematics needs to be in place.


That's why I said the vectors can be added.

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